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From: "Joris" <joris.at.lebbeke@skynet.be>
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References: <Pine.GSO.4.44.0401230953060.29988-100000@scooby.simplesystems.org> <40114F6A.1040507@pobox.com> <001901c3e1d4$9445e1f0$db04c950@dfgrrxsknr4e> <40115BFE.3000500@pobox.com>
Subject: Re: [Tiff] How to convert MINISBLACK to PHOTOMETRIC_RGB
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Date: Fri, 23 Jan 2004 18:57:21 +0100
X-UIDL: d23e758b914b828683897a0e9614c048

Frank Warmerdam wrote:
> "sample" == "band" == "channel" == "component" == ?

Thanks Frank. Now I know I finally did understand it correctly. Am I also
correct in thinking that the only proper way ignorant software (as in
software that doesn't know about how the image came about or what it is
intended to contain) can correctly interpret this 3-channel image as a
grayscale image with 2 extra channels that have no specified
application/meaning? If ignorant software were to have to render this image,
the correct thing to do is to render the first channel as grayscale, and
discard the others as far as rendering is concerned, is that right? I
realize this may also be trivial questions, but this thread is very
confusing.


Joris

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